Question

find the value of n show that k+2,4k-6,3k-3 are consecutive terms of ap

Answer 1

If these form an AP then,k -  

4k-6 - k-2 = 3k-2 - 4k+6

3k - 8 = -k + 4

3k + k = 4 + 8

4k = 12

k = 3