Question

Find the value of n so that (-3)power n+1×(-3)power5=(-3)power9

Answer 1

(-3)^n+1 × (-3)^5 = (-3) ^9
(-3)^(n+1+5) = (-3)^9 [since, a^m + a^n = a^(m+n)]
Since bases are the same powers can be equated......

Hence, n+1+5 = 9
n+6 = 9
Hence, n = 3


There ya go pal....
Hope it helped

Answer 2

(-3)
${ - 3}^{r} \times { - 3} \times { - 3}^{5} = { - 3}^{9} \\ { - 3}^{r} = { - 3}^{9 - 5 - 6} \\ =r = 3$