Question

find the value of n such that 23(4n-1)-(2n-1+n3 )=13n+43​

Answer 1

Solution →

23(4n-1)-(2n-1+3n )=13n+43

92n - 23 - 2n + 1 - 3n = 13n + 43

- 3n + 90n -22 -13 n - 43 = 0

74n - 65 = 0

n = 65/74

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