find the value of n such that n^P5 =42 n^P3 , n>4
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Step-by-step explanation:
calculating p5= n/ (n-5)
= n( n-1)(n-2)(n-3)(n-4)(n-5)/(n-5)
= n(n-1)(n-2)(n-3)(n-4)
calculating 42P3 = 42 n/(n-3)
=42n(n-1)(n-2)(n-3)/n-3)
= 42n(n-1)(n-2)
now ,
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