Math, asked by christymariya, 6 months ago

find the value of n such that n^P5 =42 n^P3 , n>4​

Answers

Answered by patelkavita921
3

Step-by-step explanation:

calculating p5= n/ (n-5)

= n( n-1)(n-2)(n-3)(n-4)(n-5)/(n-5)

= n(n-1)(n-2)(n-3)(n-4)

calculating 42P3 = 42 n/(n-3)

=42n(n-1)(n-2)(n-3)/n-3)

= 42n(n-1)(n-2)

now ,

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