Find the value of n such that :
nP4 / n-1P4 = 5/3 , n>4
from permutation and combination chapter
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np4 = n!/(n-4)! = n(n-1)(n-1)(n-3)
n-1p4 = (n-1)(n-2)(n-3)(n-4)
Now np4/n-1p4 = 5/3 i.e
3(n)(n-1)(n-2)(n-3) = 5(n-1)(n-2)(n-3)(n-4)
By removing (n-1)(n-2)(n-3) i.e
3n=5n-20
20 = 2n
n = 10.
Hope this helps:)
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