Question

Find the value of n when:
(2) 8x2^n+2 = 32​

Answer 1

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The answer is as follow

$8 \times {2}^{n + 2} = 32 \\ {2}^{n + 2 } = \frac{32}{8} \\ {2}^{n + 2} = 4 \\ {2}^{n + 2} = {2}^{2} \\ so \\ n + 2 = 2 \\ n = 2 - 2 \\ n = 0$

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Answer 2

Step-by-step explanation:

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