Question

find the value of n when (9)^2n-1=(27)^n+2

Answer 1

Answer:

n = 8

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Step-by-step explanation:

$9^{2n-1} = 27^{n+2}$

$(3^2)^{2n-1} = (3^3)^{n+2}$

$3^{4n-2} = 3^{3n+6}$

Comparing same base;

4n - 2 = 3n + 6

4n - 3n = 6 + 2

n = 8

Answer 2

Answer:

n=8

Step-by-step explanation:

i hope you understand my friend