Math, asked by 3478payalpayu, 1 year ago

Find the value of n when:

can anyone please answer this question ....​

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Answers

Answered by Anonymous
1

hey mate:-

given here

8 × 2^(n+2)=32

Answer:-

8 × 2^(n+2)=32

=> 2³ × 2^(n+2)= 32

=>2 ^3(n+2)=32

=>2^(3n+6)=2^5

we know ,

if a^m =a^n ,

then,

m=n

so,

=> 3n +6 = 5

=> 3n = 5-6

=> 3n = -1

=> n = -1/3

i hopes its helps t

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Answered by divyanshi114187
1

8×2n+2=32

Multiply 8×2

16n+2=32

2+16n=32

Solving

2+16n=32

Add '-2' to each side of the equation

2+-2+16n=32+ -2

Combine like terms: 2+ -2 =0

0+16n=32+ -2

Like terms: 32+ -2=30

16n=30

Divide each side by '16'

n=1.875

n=1.875

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