Find the value of n when:
can anyone please answer this question ....
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Answered by
1
hey mate:-
given here
8 × 2^(n+2)=32
Answer:-
8 × 2^(n+2)=32
=> 2³ × 2^(n+2)= 32
=>2 ^3(n+2)=32
=>2^(3n+6)=2^5
we know ,
if a^m =a^n ,
then,
m=n
so,
=> 3n +6 = 5
=> 3n = 5-6
=> 3n = -1
=> n = -1/3
i hopes its helps t
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Answered by
1
8×2n+2=32
Multiply 8×2
16n+2=32
2+16n=32
Solving
2+16n=32
Add '-2' to each side of the equation
2+-2+16n=32+ -2
Combine like terms: 2+ -2 =0
0+16n=32+ -2
Like terms: 32+ -2=30
16n=30
Divide each side by '16'
n=1.875
n=1.875
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