Question

find the value of nC0 + nc1+ nc2 + .....nc(n-1)​

Answer 1

Answer:

2^n-1

Step-by-step explanation:

since

nC1+nC2+...+nCn=2^n (eqn.1)

now subtract nCn from eqn.1 we get:

nC1+nC2+...+nCn-1,since nCn=1

then nC1+nC2+...nCn-1=2^n-1.