find the value of of a if X + 6 is a factor of x power 3 + 3 x power 2 + 4 x + a
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Step-by-step explanation:
- g(x)=X+6
- g(X) = 0
- X+6=0
- X=-6
- now, (-6)^3 + 3(-6)^2+4(-6)+a =0
- -216+108-24+a=0
- -132+a=0
- +a=132
so the value of a is 132 ..
hope it help you ..
thanks
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Answer:
as x+6 is a factor the root will be
x+6=0
x=-6
in the equation
(-6)^3+3(-6)^2+4(-6)+a=0
-216+108-24+a=0
-240+108+a=0
a=132
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