Question

Find the value of
of the equation
4x²-5x-3=0​

Answer 1

Step-by-step explanation:

4x^2-5x-3=0

According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :

- B ± √ B2-4AC

x = ————————

2A

In our case, A = 4

B = -5

C = -3

Accordingly, B2 - 4AC =

25 - (-48) =

73

Applying the quadratic formula :

5 ± √ 73

x = —————

8

√ 73 , rounded to 4 decimal digits, is 8.5440

So now we are looking at:

x = ( 5 ± 8.544 ) / 8

Two real solutions:

x =(5+√73)/8= 1.693

or:

x =(5-√73)/8=-0.443

Two solutions were found :

x =(5-√73)/8=-0.443

x =(5+√73)/8= 1.693