Question

find the value of of (x-y) , if 3x+2y=8 ; 2x+3y=7
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Answer 1

Answer:

$\large\purple{\underline{ᗩɳรωεɾ♬♬:}}$

Given equations:

${3x}+{2y}={8}$

${2x}+{3y}={7}$

SO SUBTRACT BOTH EQUATIONS..

we get

$\large{ {x}-{y}={1}}$

$\large{\boxed{ Answered \: By: \: ɱαɳเcρรყcɦσ68}}$

Answer 2

Answer:

Question

• Find the value of of (x-y) , if 3x+2y=8 ; 2x+3y=7

Answer

Given :-

• 3x + 2y = 8 ; 2x + 3y = 7

To find :-

• Values of x and y

Method used :-

Equations of the form ax + by = c and bx + ay = d can be solved by using the following steps :

• Step 1 Add the two equations.
• Step 2 Subtracting the two equations.
• Step 3 Add and Subtracting the equations obtained in Step 1 and Step 2 to get the values of x and y.

Solution :-

Let 3x + 2y = 8.........(1)

and 2x + 3y = 7.........(2)

Adding (1) and (2), we get

$\bf\implies \:5x + 5y = 15$

$\bf\implies \:5(x + y) = 15$

$\bf\implies {3\cancel\dfrac{15}{5}=x + y}$

$\bf\implies \:x + y = 3.......(3)$

Now, Subtracting (2) from (1), we get

$\bf\implies \:x - y = 1......(4)$

Now, to get the values of x and y, add (3) and (4), we get

$\bf\implies \:2x = 4$

$\bf\implies \:{2\cancel\dfrac{4}{2}=x}$

$\bf\implies \:x = 2$

Put x = 2 in equation (3) we get

$\bf\implies \:2 + y = 3$

$\bf\implies \:y = 1$

$\bf\implies \:x = 2 \: and \: y = 1$

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