find the value of of27xcube+8y cube,If
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Given that,
1. 3x + 2y = 20
2. xy = 14 / 9
We have to find,
→ 27x³ + 8y³
We must use the identity:
a³ + b³ = (a + b)(a² + b² - ab)
So, let,
a = 3x
b = 2y
→ a + b = 3x + 2y = 20
→ a³ + b³ = 27x³ + 8y³
→ ab = 6xy = 6 • 14 / 9 = 28 / 3
=> 3ab = 3 • 28 / 3 = 28
=> 3x + 2y = 20
=> a + b = 20
=> (a + b)² = 20²
=> a² + b² + 2ab = 400
=> a² + b² + 2ab - 3ab = 400 - 3ab
=> a² + b² - ab = 400 - 28
=> a² + b² - ab = 372
Now,
27x³ + 8y³
=> a³ + b³
=> (a + b)(a² + b² - ab)
=> 20 • 372
=> 7440
Hence 7440 is the answer.
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