Find the value of other five trignometic functions if cosx=
where x lies in 3rd quadrant
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Answer:
Step-by-step explanation:
Cosx = -1/2 , where x lies in third quadrant.
We know, in 3rd quadrant tang∅, and cot∅ are positive.
Cosx = -1/2 = b/h
So, p = √(h² - b²) = √(2²-1²)
= ±√3
Now, sinx = P/h = ±√3/2
But sinx is negative in 3rd quadrant so, sinx = -√3/2
cosecx = 1/sinx = 1/(-√3/2) = -2/√3
Tanx = P/b = ±√3/1
we know, tanx is positive so,
Tanx = √3
Cotx = 1/tanx = 1/√3
Secx = 1/cosx = 1/(-1/2) =-2
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