Question

Find the value of other five trignometic functions if cosx=
$- \sqrt{3} \div 2$
where x lies in 3rd quadrant​

Answer 1

Answer:

Step-by-step explanation:

Cosx = -1/2 , where x lies in third quadrant.

We know, in 3rd quadrant tang∅, and cot∅ are positive.

Cosx = -1/2 = b/h

So, p = √(h² - b²) = √(2²-1²)

= ±√3

Now, sinx = P/h = ±√3/2

But sinx is negative in 3rd quadrant so, sinx = -√3/2

cosecx = 1/sinx = 1/(-√3/2) = -2/√3

Tanx = P/b = ±√3/1

we know, tanx is positive so,

Tanx = √3

Cotx = 1/tanx = 1/√3

Secx = 1/cosx = 1/(-1/2) =-2