Question

Find the value of other five trigonometric ratios: cos x= -5/12, x lies in second quadrant

Answer 1

Step-by-step explanation:

Let,

cos x = -5/12

we know that,

sin2x + cos2x = 1

sin2x +(-5/12) 2 = 1

sin2x = 1 - 25/144

sin2x = 119/144

sin x = √119/12

also,

cosec x = 1/ sin x

cosec x = 12/√119

Now,

tan x = sin x/cos x

tan x= √119/5

also,

cot x = 1/tan x

cot x = 5/√119

now,

sec x = 1/cos x

sec x = -12/5