Question

find the value of others five trigonometry ratios if tanx=-5/12
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Answer 1

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Answer 2

Step-by-step explanation:

tanx= -5/12

∴perpendicular= -5 and base= 12

By Pythagora's theorem,

h^2= p^2 + b^2

=> h = √(-5)^2 + (12)^2

= √25+144

= √169

= 13

∴ Hypotenuse= 13

Other 5 T-ratios:

1) sinx= p/h = -5/13

2) cosx= b/h = 12/13

3)cosecx= h/p = -13/5

4)secx= h/b = 13/12

5)cotx= b/p= -12/5