Question

find the value of p(0),p(1)and p(-2) for the polynomial p (x)=x^3-3x+5​

Answer 1

Answer:

given p (x)=x^3-3x+5.

p (0)=5.

again, p (1)=1-3+5.

=3.

again, p (-2)=-8+6+5.

=3.

Answer 2

Hello Friend.

Here is ur answer below,,

1.

p(x) = x^3-3x+5

p(0) = 0^3-3×0+5=5

2.

p(1) = 1^3-3×1+5 = 3

3.

p(-2) = (-2)^3-3×(-2)+5 =3

I hope that helps you