Question

find the value of p(0),p(-1) for - p(t) =2/3t² 1/3t+1/3​

Answer 1

Answer:

Given: p(t)=t

Given: p(t)=t 3

Given: p(t)=t 3 −1

Given: p(t)=t 3 −1 p(1)=1

Given: p(t)=t 3 −1 p(1)=1 3

Given: p(t)=t 3 −1 p(1)=1 3 −1

Given: p(t)=t 3 −1 p(1)=1 3 −1 =1−1=0

Given: p(t)=t 3 −1 p(1)=1 3 −1 =1−1=0 p(−2)=(−2)

Given: p(t)=t 3 −1 p(1)=1 3 −1 =1−1=0 p(−2)=(−2) 3

Given: p(t)=t 3 −1 p(1)=1 3 −1 =1−1=0 p(−2)=(−2) 3 −1

Given: p(t)=t 3 −1 p(1)=1 3 −1 =1−1=0 p(−2)=(−2) 3 −1 =−8−1=−9

Answer 2

Step-by-step explanation:

p(1) =(1)^-1=1-1=0

p(2)=2^-2=6

p(0)=0^-1=-2

p(-1)=(-1)^=-1-1=-2

p(-2)=-2^=-9