Question

find the value of p(0),p(1),p(2) if p(t)=2+t+2t^2-t^3​

Answer 1

Step-by-step explanation:

p(t)=2+t+2t²-t³

p(0)=2+0+2.0²-0³

=2+0+0-0

=2

p(1)=2+1+2.1²-1³

=2+1+2-1

=3+1

=4

p(2)=2+2+2.2²-2³

=2+2+8-8

=4+0

=4

Answer 2

Step-by-step explanation:

$\tt \: p(1) \: = 2 + 1 + 2 {(1)}^{2} - {(1)}^{3} \\ \\ \\ = \tt \: 2 + 1 + 2 - 1 \\ \\ \\ = \tt5 - 1 \\ \\ \\ = \tt \blue{4}$

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$\tt \: p(0) \: = 2 + 0 + 2 {(0)}^{2} - {(0)}^{3} \\ \\ \\ = \tt \: 2 + 0 + 0 - 1 \\ \\ \\ = \tt \green{2}$

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$\tt \: p(2) \: = 2 + 2 + 2 {(2)}^{2} - {(2)}^{3} \\ \\ \\ = \tt \: 2 + 2+ 2- 1 \\ \\ \\ = \tt \orange{4}$

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