Question

find the value of p(1/2)for p(z)=zpower 4-zpower2+z​

Answer 1

Answer:

Step-by-step explanation:

P(z)=z^4-z^2+z

P(1/2)=(1/2)^4+(1/2)^2+(1/2)

P(1/2)=(1/16)+(1/4)+(1/2)

P(1/2)={[(1*1)+(1*4)+(1*8)]/16}

P(1/2)=(1+4+8)/16

P(1/2)=13/16