Math, asked by YOURFATHE, 2 months ago

Find the value of P(1) for the polynomial p(x)=10x-4x square-3

Answers

Answered by dk1572005
1

Answer:

3

Step-by-step explanation:

p(x)= 10x-4x²-3

p(1)= 10×1-4×(1)²-3

= 10-4-3

= 10-7

= 3

Therefore, the value of P(1) for the polynomial p(x)=10x-4x²-3 is 3

Answered by Flaunt
13

Given

p(x) = 10x-4x²-3

To Find

We have to find p(1)

\sf\huge\bold{\underline{\underline{{Solution}}}}

We have function p(x) = 10x-4x²-3

Rewriting the term => -4x²+10x-3

Now, we have to find p(1)

p(1) = p(x)

Comparing the coefficient we find x = 1

So, we have to find p(x) = -4x²+10x-3 at x=1

Note : any change in p(x) will make a change in the whole function.

Now,p(1)= -4(1)²+10(1)-3

=>p(1)= -4+10-3

=>p(1)= -4+7

=>p(1)= 3

Therefore,the value of p(1) is 3

Extra information=>

➥The above function is a quadratic equation as highest power is 2.

➥p(x)=y here ,p is the function and x is an input which gives output say 'y'.

➥We can find infinite number of output of p(x) by putting infinite number of values into p(x).

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