Find the value of P(1) for the polynomial p(x)=10x-4x square-3
Answers
Answer:
3
Step-by-step explanation:
p(x)= 10x-4x²-3
p(1)= 10×1-4×(1)²-3
= 10-4-3
= 10-7
= 3
Therefore, the value of P(1) for the polynomial p(x)=10x-4x²-3 is 3
Given
p(x) = 10x-4x²-3
To Find
We have to find p(1)
We have function p(x) = 10x-4x²-3
Rewriting the term => -4x²+10x-3
Now, we have to find p(1)
p(1) = p(x)
Comparing the coefficient we find x = 1
So, we have to find p(x) = -4x²+10x-3 at x=1
Note : any change in p(x) will make a change in the whole function.
Now,p(1)= -4(1)²+10(1)-3
=>p(1)= -4+10-3
=>p(1)= -4+7
=>p(1)= 3
Therefore,the value of p(1) is 3
Extra information=>
➥The above function is a quadratic equation as highest power is 2.
➥p(x)=y here ,p is the function and x is an input which gives output say 'y'.
➥We can find infinite number of output of p(x) by putting infinite number of values into p(x).