find the value of p
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sum of the angles in a triangle = 180°
i.e 100° +45°+ P = 180°
= 180-145= P
= 35°=P
next, sum of the angles in a triangle = 180°
65°+40°+q= 180°
= 180°-105= q
= 75° =q
Answered by
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in ∆ (sum of angles of a triangle is equal to 180°)
100°+45°+^p = 180°
145°+^p = 180°
^p = 180°- 145°
^p = 35°
therefore, ^p = 35°
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