find the value of p(-2/3) for p(y)=2y^3-y^2-13y-6
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Given :-
- p(y) = 2y³ - y² - 13y - 16
To Find :-
Answer :-
p(y) = 2y³ - y² - 13y - 16
y = -2/3 put,
p( -2/3) = 2(-2/3)³ - ( -2/3 )² - 13 ( -2/3 ) - 6
= -16 / 27 - 4 / 9 + 26 / 3 - 6
= - 0.59 - 0.44 + 8.66 - 6
= 1.63
Conclusion :-
∴ The value of = 1.63.
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