find the value of p(-2/3) for p(y)=2y-y^3-y^3-13y-6
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p(-2/3)=2(-2/3)-2(-2/3)^3-13(-2/3)-6
=-4/3+16/27+26/3-6
=22/3-16/27-6
=-92/27
=-4/3+16/27+26/3-6
=22/3-16/27-6
=-92/27
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HarshaSankar149:
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p(y)=2y-y³-y³-13y-6
p(-2/3)=2(-2/3)-(-2/3)³-(-2/3)³-13(-2/3)-6
= -4/3-(-8/27)-(-8/27)-(-26/3)-6
= -4/3+8/27+8/27+26/3-6
= -4/3+26/3+8/27+8/27-6
= 22/3+16/27-6
= 594/81+48/81-6
= 642/81-6
= 214/27-6
= 214-162/27
= 52/27
Answer=52/27
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p(-2/3)=2(-2/3)-(-2/3)³-(-2/3)³-13(-2/3)-6
= -4/3-(-8/27)-(-8/27)-(-26/3)-6
= -4/3+8/27+8/27+26/3-6
= -4/3+26/3+8/27+8/27-6
= 22/3+16/27-6
= 594/81+48/81-6
= 642/81-6
= 214/27-6
= 214-162/27
= 52/27
Answer=52/27
PLS MAKE MY ANSWER BRAINLIEST
FOLLOW ME IF I HELPED YOU
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