Question

find the value of p(2/3) for p(y) = 2y3-y2-13y-6

Answer 1

Answer:

13818-y2-13y

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Answer 2

Answer:  44/27

Step-by-step explanation:p(y) = 2y³ - y² -13y - 6

for finding p(-2/3) put y = -2/3 in the given polynomial

p(-2/3) = 2(-2/3)³ - (-2/3)² - 13(-2/3) - 6

p(-2/3) = -16/27 - 4/9 + 26/3 - 6

p(-2/3) = (-16 - 4*3 + 26*9 - 6*27)/27

p(-2/3) = (-16 - 12 + 234 - 162)/7

p(-2/3) = 44/27