Math, asked by somnath246ggmailcom, 1 year ago

find the value of p(-2/3)for p(y)=2y³-y²-13y-6

Answers

Answered by Swarup1998
10
Ans.

Given,

p(y)=2y³-y²-13y-6

Now,

p(-2/3)=2(-2/3)³ - (-2/3)² - 13(-2/3) - 6

= -16/27 - 8/9 + 26/3 - 6

= (-16 - 24 + 234 - 162)/27

= 32/27
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