find the value of p(2) if p(y) =y square-y+1
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Answer:
Answer is P(2) = 3
Step-by-step explanation:
- P(y) = y² - y + 1
- So,
- P(2) = (2)²-2+1
- P(2)= 4-2+1
- P(2) = 3
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