Math, asked by aryanarora97, 9 months ago

Find the value of p(2) + p(-2) for the polynomial x^2-3x+1
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Answers

Answered by srushtirajput
0

hope it helps you... thanks

Attachments:
Answered by pulakmath007
9

\displaystyle\huge\green {\underline{\underline{Solution}}}

GIVEN

p(x) =  {x}^{2}  - 3x + 1

TO DETERMINE

p(2) + p( - 2)

EVALUATION

p(x) =  {x}^{2}  - 3x + 1 \:  \: ..........(1)

So in order to find p(2) we put 2 in place of x in both sides of (1)

p(2) =  {2}^{2}  - (3 \times 2) + 1 = 4 - 6 + 1 =  - 1

Now in order to find p(2) we put - 2 in place of x in both sides of (1)

p( - 2) =  {( - 2)}^{2}  - 3 \times ( - 2) + 1 = 4 + 6 + 1 = 11

Hence

p(2) + p( - 2) =  - 1 + 11 = 10

RESULT

 \red{ \fbox{p(2) + p( - 2) =  10}}

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