Question

Find the value of "p"
27^p=9^2p-2​

Answer 1

Step-by-step explanation:

27p = 9/3p

☛ 27p × 3p = 9

☛ 81p² = 9

☛ p² = 9/81

☛ p² = 1/9

☛ √p² = √(1/9)²

∴ p = 1/3

Hence, the value of p is 1/3

$$\rule{195}{2}$$

Verification :-

27p = 9/3p

By putting the value of as 1/3

☛ 27 × 1/3 = 9/(3×1/3)

☛ 9 × 1 = 9/1

☛ 9 = 9

∴ LHS = RHS

Hence, the value of p is 1/3

$$\rule{195}{2}$$

Points to remember :

(+) changes to (-)

(-) changes to (+)

(×) changes to (÷)

(÷) changes to (×)

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