Question

Find the value of ‘p’ , (3)2pFind the value of ‘p’ , (3)2p–5 = (27)–5
.–5 = (27)–5
.

Answer 1

Answer:

125/27.

Step-by-step explanation:

125/27 So ⇒(5/3)^{-x} × (5/3)^2x =125/27 Further simplifying the expression … ... Find the value of p for which (3/5)^p(5/3)^2p=125/27.

Answer 2

3x2p=6p

3x2p-5=27-5

6p-5=22

6p=22+5

6p=27

p=27/6