Question

find the value of p.... 5^2p+1÷25=125​

Answer 1

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{5}^{2x + 1} \div 25 = 125 \\ = > {5}^{2x + 1} \div {5}^{2} = 125 \\ = > {5}^{2x + 1 - 2} = {5}^{3}

Now, but equating the power we have,

=> 2x +1 - 2 = 3

=> 2x - 1 = 3

=> 2x = 3+1

=> 2x = 4

=> x = 4/2

=> x = 2

Hence, the value of x = 2..