Find the value of ‘p and also find the measure of BOC and AOD.
Answers
Step-by-step explanation:
We know that the sum of all the angles in a straight line is 180
We know that the sum of all the angles in a straight line is 180 o
We know that the sum of all the angles in a straight line is 180 o
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o x=50
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o x=50 o
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o x=50 o
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o x=50 o ∠COD=50
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o x=50 o ∠COD=50 o
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o x=50 o ∠COD=50 o
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o x=50 o ∠COD=50 o ∠AOD=x+10
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o x=50 o ∠COD=50 o ∠AOD=x+10 o
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o x=50 o ∠COD=50 o ∠AOD=x+10 o
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o x=50 o ∠COD=50 o ∠AOD=x+10 o =60
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o x=50 o ∠COD=50 o ∠AOD=x+10 o =60 o
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o x=50 o ∠COD=50 o ∠AOD=x+10 o =60 o
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o x=50 o ∠COD=50 o ∠AOD=x+10 o =60 o ∠BOC=x+20=70
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o x=50 o ∠COD=50 o ∠AOD=x+10 o =60 o ∠BOC=x+20=70 o
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o x=50 o ∠COD=50 o ∠AOD=x+10 o =60 o ∠BOC=x+20=70 o
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o x=50 o ∠COD=50 o ∠AOD=x+10 o =60 o ∠BOC=x+20=70 o ∴ ∠COD=50
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o x=50 o ∠COD=50 o ∠AOD=x+10 o =60 o ∠BOC=x+20=70 o ∴ ∠COD=50 o
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o x=50 o ∠COD=50 o ∠AOD=x+10 o =60 o ∠BOC=x+20=70 o ∴ ∠COD=50 o , ∠AOD=60
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o x=50 o ∠COD=50 o ∠AOD=x+10 o =60 o ∠BOC=x+20=70 o ∴ ∠COD=50 o , ∠AOD=60 oand ∠BOC=70
We know that the sum of all the angles in a straight line is 180 o ∠BOC+∠COD+∠AOD=180 o .x+20+x+x+10=180 o 3x+30=180 o 3x=150 o x=50 o ∠COD=50 o ∠AOD=x+10 o =60 o ∠BOC=x+20=70 o ∴ ∠COD=50 o , ∠AOD=60 oand ∠BOC=70 o.