Question

find the value of p and q
(a) x^2 +4x -p=(x-q)(x+7)
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Answer 1

Answer:

p=21 ; q=3

Step-by-step explanation:

x^2+4x-p=(x-q)(x+7)

=x^2+(-q+7)x--7q

Equating the coefficients

4=-q+7 ; -p=-7q

q=7-4. ; p=7q

=3 ; p=7*3=21

Answer 2

Given,

An equation x² +4x -p = (x-q)(x+7)

To Find,

The value of p and q.

Solution,

The given equation is x² +4x -p = (x-q)(x+7)

Now, solving the R.H.S

(x-q)(x+7)

x(x+7)-q(x+7)

x²+7x-qx-7q

x²+x(7-q)-7q

Now equating the coefficients of L.H.S and R.H.S

7-q = 4

q = 3

-7q = -p

p = 7*3 = 21

Hence, the value of p is 21 and q is 3.