Question

Find the value of p and q for which 3/2 and -3 are two roots of px² + qx - 9 = 0.
Ans => (p = 2, q = 3)
Plz solve it.

Answer 1

Given,

³/2 & -3 are the roots of the equation.

$p {x}^{2} + qx - 9 = 0$

Using the root ³/2 we get that,

$\frac{9p}{4} + \frac{3q}{2} - 9 = 0$

or,

$p = \frac{2(9 - 3q)}{9}$

Again, Using the root -3 & the value of p we get that

Answer 2

Answer:

p= 2 and q = 3

Step-by-step explanation:

px² + qx - 9 = 0.

sum of rootes = -q/p

3/2-3 = -q/p

- 3/2 =-q/p

product of root = -9/p

-9/2= -9/p

therefore p= 2

- 3/2 =-q/2

q = 3

mark my answer as brainliest please.