Find the value of ‘p’ and ‘q’ for which the following pair of linear equations has infinite number of solutions. 2x + 3y = 7 , 2px +(p + q)y = 28
Answers
Answer:
For infinite many solution,
now,
Hence P = 4 & Q = 8. Ans.
Given:-
The equations are -
- 2x + 3y = 7
- 2px + ( p + q )y = 28
To Find :-
The value of p and q
Solution:-
2x + 3y = 7
2px + ( p + q )y = 28
Now, Comparing both the equations to the standard form ax + by + c = 0 we get,
2x + 3y -7 = 0 ......(i)
2px + ( p + q )y - 28 = 0 .....(ii)
Here , in eq (i)
a1 = 2 , b 1= 3 , c1 = -7
In eq(ii)
a 2= 2p , b 2= (p + q) , C2 = - 28
For infinitely many solution ,
⇒
⇒
so,
⇒
Now , by cross multiplication ,
⇒2p + 2q = 6p
⇒2p - 6p = -2q
⇒-4p = -2q
⇒2p = q ..... ( iii)
Now,
Again, By cross multiplication
7p + 7q = 84
p+ q = 84 /7
p + q = 12 .....( iv)
Now putting the value of q that we find out in eq (iii) in eq( iv) , we get
p+ q = 12
p + 2p = 12
3p = 12
p = 12 / 3
p = 4
Therefore, the value of p is 4
Now , we get 2p = q in eq (iii)
so , putting the value of p in eq (iii)
2 × 4 = q
q = 8
Hence the value of p is 4 and q is 8 .