Question

find the value of p and q if x=1 and y =2 are the solution of 2x-py+2=0 and 3x-y-p-2=0​

Answer 1

2-2p+2 = 0

4-2p= 0

-2p = -4

So,p= 2

and,3-2-q-2 = 0

-1-q = 0

-q = 1

q = -1

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Answer 2

Answer:

p=1 and q=-1

Step-by-step explanation:

as q is not mentioned in the equation

So i am assuming that the expression is given like

$2x-py+2=0\\and \\3x-2y-q-2=0$

since x=1 and y= 2 is the solution of the equation

so the value of these equations will be 0 at x=1 and y=2

hence

$2*1 - p*2 +2 =0\\=> 4-2p=0\\=> 2p=4\\=> p=2$

and

$3*1-2-q-2 =0\\=> q= 3-2-2\\=> q=3-4\\=> q=-1$

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