find the value of p and q so that (x-1) and (x-2) are the factors of x3+10x2+px+q
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answer for the question is
put the vale of x=1
(1)3+10(1)2+p(1)+q=0
3+20+p+q=0
23+p=-q ..............eq 1
again put the value of x=2
(2)3+10(2)2+p(2)+q=0
6+40+2p+q+0
46+2p+q=0
2p+q=-46
now put the value of x from eq1
2p+(23+p)=-46
3p+23=-46
3p=-46-23
p=-69/3
p=-23
q=23+p
=23+(-23)
=0
hope my anwers help you and if u think it is really helpful then pls mark it as brainliest answer
put the vale of x=1
(1)3+10(1)2+p(1)+q=0
3+20+p+q=0
23+p=-q ..............eq 1
again put the value of x=2
(2)3+10(2)2+p(2)+q=0
6+40+2p+q+0
46+2p+q=0
2p+q=-46
now put the value of x from eq1
2p+(23+p)=-46
3p+23=-46
3p=-46-23
p=-69/3
p=-23
q=23+p
=23+(-23)
=0
hope my anwers help you and if u think it is really helpful then pls mark it as brainliest answer
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