Question

Find the value of p and q ; x^2+px-9=(x-1)(x+q) [x^2 means 'square of x']


Ans. p=8 and q=9

Answer 1

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Answer 2

Answer:

p=8 and q=9

Step-by-step explanation:

${x }^{2} + px - 9 = (x - 1)(x + q) \\ {x}^{2} + px - 9 = {x}^{2} + qx - x - q \\ px - qx + x + q = 9 \\ x(p - q) + q = 9 - x \\ q + x(p - q) = 9 - x \\ comparing \: both \: side \: \\ q = 9 \: and \: x(p - q) = - x \\ and \: p - q = - 1 \\ p = 9 - 1 \\ q = 9 \: and \: p = 8$