Question

find the value of p(E)+p(not E)​

Answer 1

1...

the probablity of happening an event and not bappening is always 1

hope it helps...

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Answer 2

Answer:

Probability of E + Probability of not E is always 1.

So, P ( E ) + P ( not E ) = 1.

• Probability of a sure event is 1.
• Probability of an event that isn't sure is between 0 and 1.
• Probability of the event that is impossible is 0.

If there is a chance of probability of E to be 1, obviously the chance of probability of not E will be 0, totalling the value of the equation as 1.

( P of E + P of not E = 1 )

If the probability of the event lies between 0 and 1 as per the rule, the other one should also like between 0 and 1, and as per the rule if both the probabilities are added it will be equal to 1.

So, P of E1 + P of E2 = 1.

Now, P of E2 = P of not E1.

So, P of E + P of not E = 1

$\rule{200}2$