Question

find the value of P foe which 3x^2-P√3x+4=0 has no root​

Answer 1

●Given Eq :

•f(x) = 3x² -p√3x + 4 = 0

•The above eq and no real roots i.e D < 0

means D →(-ve)

●To Find :

•Value of p

◆Solution :

a = 3 ; b = -p√3 ; c = 4

$\sf \: D = {b}^{2} - 4ac \\ \\ \sf D = (-p \sqrt{3})² - 4(3) (4) \\ \\ \sf = 3p²-48 < 0 \\ \\ \sf = 3p² < 48 \\ \\ \sf = p² < 16 \\ \\ \sf \: \pink{ \sqrt{16} = 4 = p}$