Math, asked by Falguny, 1 year ago

Find the value of p, for the following pair of equation 3x-y-5=0 and 6x-2y-p=0 are parallel

Answers

Answered by Anonymous
48
Hey user !!

Here is your answer !!

Refer to the given attachment please !!

Hope it is satisfactory ^_^
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Falguny: thanks alot
Anonymous: My plzr ^_^
Answered by smithasijotsl
1

Answer:

The pair of linear equations 3x-y-5=0 and 6x-2y-p=0 are parallel for all the values of 'p' other than 10

Step-by-step explanation:

Given

3x-y-5=0 and 6x-2y-p=0 are parallel

To find,

The value of 'p'

Recall the concept

A pair of linear equations a_1x+b_1y+c1 = 0  a_2x+b_2y+c_2 = 0 are parallel if \frac{a_1}{a_2}  = \frac{b_1}{b_2}\neq  \frac{c_1}{c_2} -------------------(1)

Solution

Given equations are

3x-y-5=0 and 6x-2y-p=0

Compare the given equations with  a_1x+b_1y+c1 = 0 and a_2x+b_2y+c_2 = 0  we get

a_1 = 3 ,a_2 = 6 , b_1 = -1, b_2 = -2 c_1 = -5 and c_2 = -p

Substituting these values in the condition(1) we get

\frac{3}{6} = \frac{-1}{-2}   \neq  \frac{-5}{-p}

\frac{1}{2} \neq \frac{5}{p}

p ≠10

The pair of linear equations 3x-y-5=0 and 6x-2y-p=0 are parallel for all the values of 'p' other than 10

#SPJ3

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