Question

Find the value of p for the quadratic equation (p − 3)x² - px + 2x + 3 = 0, so that it has two equal roots​

Answer 1

Step-by-step explanation:

• it has equal roots if
• ${b}^{2} - 4ac = 0$
• $(2 - {p)}^{2} - 4(p - 3)3$ = 0
• $4 - 4p + {p}^{2} - 12(p - 3)$ = 0
• ${p}^{2} - 16p + 40$ = 0

$p = 12.899$

$or$

$p = 3.101$