Question

Find the value of p for which 2^{3p}\div 2^{-3} = 2^{9}

Answer 1

Answer:

p=2

Step-by-step explanation:

$\frac{ \: \: {2}^{ 3p} \: }{ {2}^{ - 3} } = {2}^{9} \\ {2}^{3p + 3} = {2}^{9} \\ when \: bases \: are \: common \: take \: exponents \: equal \\ so \\ \\ 3p + 3 = 9 \\ p = 2$