Math, asked by roselotha, 8 months ago

Find the value of p for which (2/7)^5 × (2/7)^-6 = (2/7)^2p-1​

Answers

Answered by deepakbhaskar027
9

Answer:

p=1/2

Step-by-step explanation:

(2/7)^5×(2/7)^-6=(2/7)^2p-1

(2/7)^5+(-6)=(2/7)^2p-1

-1=2p-1

p=1/2

Answered by Anonymous
19

❣️Hi❣️

Here is your answer =>

p=1/2

Step-by-step explanation:

(2/7)^5×(2/7)^-6=(2/7)^2p-1

(2/7)^5+(-6)=(2/7)^2p-1

-1=2p-1

p=1/2

‼️ I hope it will help u‼️

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