Question

find the value of p for which (2/7)5 × (2/7)-6 = (2/7)2p-1
Required answer =0
Please Yrrrr help​

Answer 1

Answer:

-678/49

Step-by-step explanation:

(2/7)×5 × (2/7)-6=(2/7)2p-1

(2/7)×5 × (2/7)-6=(2/7)2p-1:- 10/7 × (2-42)/7 = (4p-2)/7

(2/7)×5 × (2/7)-6=(2/7)2p-1:- 10/7 × (2-42)/7 = (4p-2)/7:- 10/7 × (-40/7) = (4p-2)/7

(2/7)×5 × (2/7)-6=(2/7)2p-1:- 10/7 × (2-42)/7 = (4p-2)/7:- 10/7 × (-40/7) = (4p-2)/7:- -400/49 = 4p-2/7

:- USING CROSS MULTIPLICATION

:- -400 × 7 = 49(4p-2)

:- -2800 = 196p-98

:- 196p = -2702

:- p = -2702/196

:- p = -678/49

SORRY MY ANSWER IS NOT COMING 0

HOPE YOU UNDERSTAND

Answer 2

Answer:

Step-by-step explanation:

hope hellp u ☺