find the value of p for which 4x^4 *+ 2x^3 - 3x^2 -px - 28 has -2 as its zero
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hope this will help you
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replyr:
you forget to multiply p by 2
sorry its a silly mistake
that's fine every does
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4
putting x as -2,we have
P(-2)= 4(-2)^4+2(-2)^3-3(-2)^2-p(-2)-28
0= 4*16+2(-8)-3*4+2p-28 since P(-2)=0
0 =64-16-12+2p-28
0=8+2p
P=-8/2
P=-4
P(-2)= 4(-2)^4+2(-2)^3-3(-2)^2-p(-2)-28
0= 4*16+2(-8)-3*4+2p-28 since P(-2)=0
0 =64-16-12+2p-28
0=8+2p
P=-8/2
P=-4
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