Find the value of p for which a(6,-3),b(2,3),c(4,p)are collinear
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- If the Given points are collinear then the area of the ∆ formed by these points = 0
- Area of in co-ordinate geometry;
But for the Given situation;
Given points;
- A(6,-3)
- B(2,3)
- C(4,p)
Thus using the formula;
- 6(3-p) + 2(p+3) + 4(-3-3) = 0
- 18 - 6p + 2p + 6 + 4(-6) = 0
- ( -6p +2p ) + (18 + 6 - 24)=0
- -4p + (24 - 24) = 0
- -4p = 0
- p = 0
#answerwithquality
#BAL
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