find the value of p for which one root is 6 times of another px^2-14x+8=0
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Let the roots be β and 6β
px²-14x+8
β+6β=-b÷a
7β=14÷p
β=2÷p
β×6β=c÷a
6β²=8÷p
6(2÷p)²=8÷p
6×4÷p²=8÷p
24÷p=8
3÷p=1
p=3
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