Question

find the value of p for which one root of the equadratic equation px2-14x+8=0 is 6time of the other

Answer 1

let one root be x and other be y
acc to ques
x=6y
now sum of zeroes =-b/a
x+y=-(-14)/p
6y+y=14/p
7y=14/p
y=14/7×p
y=2/p

and product of zeroes=c/a
xy = 8/p
6y×y=8/p
6y^2 = 8/p ......eq1
as we know y=2/p
just put the value of y in eq 1 and get the value of p

I hope u get it if still have any doubts u can ask

thank u