Find the value of p, for which one root of the quadratic equation px²-14x+8=0
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Answered by
6
X=1 as 1 is root of the quadratic equation.
Therefore, p(1) -14(1)+8= 0
P - 14 +8=0
P= 14-8
P= 6
Therefore, p(1) -14(1)+8= 0
P - 14 +8=0
P= 14-8
P= 6
Answered by
0
Answer:
X=1 as 1 is root of the quadratic equation.
Therefore, p(1) -14(1)+8= 0
P - 14 +8=0
P= 14-8
P= 6
Step-by-step explanation:
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